🏆 Daily Math Board Challenge (2026 Edition)
Check whether (x + 1)² = 2(x − 3) is a quadratic equation.
🎯 Chapter Readiness Score35%
⚡ Key Formulas at a Glance
Formula (Hover/Click)
Quadratic Formula
x = (−b ± √(b²−4ac)) / 2a
Formula (Hover/Click)
Discriminant (Δ)
Δ = b² − 4ac (Δ>0 distinct, Δ=0 equal, Δ<0 no real)
Formula (Hover/Click)
Sum of Roots (α+β)
Formula (Hover/Click)
Product of Roots (αβ)
Formula (Hover/Click)
Completing Square
(x + b/2a)² = (b² − 4ac) / 4a²
Formula (Hover/Click)
Equation from Roots
x² − (Sum)x + (Product) = 0
🔍
1NCERT Standard • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
2CBSE Board 2024 • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
3NCERT Standard (Variant #3) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
4CBSE Board 2024 (Variant #4) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
5NCERT Standard (Variant #5) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
6CBSE Board 2024 (Variant #6) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
7NCERT Standard (Variant #7) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
8CBSE Board 2024 (Variant #8) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
9NCERT Standard (Variant #9) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
10CBSE Board 2024 (Variant #10) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
11NCERT Standard (Variant #11) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
12CBSE Board 2024 (Variant #12) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
13NCERT Standard (Variant #13) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
14CBSE Board 2024 (Variant #14) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
15NCERT Standard (Variant #15) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
16CBSE Board 2024 (Variant #16) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
17NCERT Standard (Variant #17) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
18CBSE Board 2024 (Variant #18) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
19NCERT Standard (Variant #19) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
20CBSE Board 2024 (Variant #20) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
21NCERT Standard (Variant #21) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
22CBSE Board 2024 (Variant #22) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
23NCERT Standard (Variant #23) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
24CBSE Board 2024 (Variant #24) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
25NCERT Standard (Variant #25) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
26CBSE Board 2024 (Variant #26) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
27NCERT Standard (Variant #27) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
28CBSE Board 2024 (Variant #28) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
29NCERT Standard (Variant #29) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
30CBSE Board 2024 (Variant #30) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
31NCERT Standard (Variant #31) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
32CBSE Board 2024 (Variant #32) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
33NCERT Standard (Variant #33) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
34CBSE Board 2024 (Variant #34) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
35NCERT Standard (Variant #35) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
36CBSE Board 2024 (Variant #36) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
37NCERT Standard (Variant #37) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
38CBSE Board 2024 (Variant #38) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
39NCERT Standard (Variant #39) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
40CBSE Board 2024 (Variant #40) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
41NCERT Standard (Variant #41) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
42CBSE Board 2024 (Variant #42) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
43NCERT Standard (Variant #43) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
44CBSE Board 2024 (Variant #44) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
45NCERT Standard (Variant #45) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
46CBSE Board 2024 (Variant #46) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
47NCERT Standard (Variant #47) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
48CBSE Board 2024 (Variant #48) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
49NCERT Standard (Variant #49) • 2 Marks2 Marks
Evaluate the exact mathematical value for Quadratic Equations when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Quadratic Equations: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
50CBSE Board 2024 (Variant #50) • 3 Marks3 Marks
Solve the exact board examination equation for Quadratic Equations: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2