GSEB Std 10 (SSC) • 2024 • 4 Marks

Pair of Linear Equations in Two Variables: Reducible Linear System of Equations

Official examination question with verified M1/A1 mark scheme and step-by-step mathematical reasoning.

Problem Statement

Solve the pair of equations for $x$ and $y$: $\frac{2}{\sqrt{x}} + \frac{3}{\sqrt{y}} = 2$ $\frac{4}{\sqrt{x}} - \frac{9}{\sqrt{y}} = -1$

Verified Solution & Marking Scheme

Substitute u = 1/√x and v = 1/√y
Let $u = \frac{1}{\sqrt{x}}$ and $v = \frac{1}{\sqrt{y}}$: $2u + 3v = 2$ ...(1) $4u - 9v = -1$ ...(2)
Solve the Linear System for u and v
Multiply equation (1) by 3: $6u + 9v = 6$ Add to equation (2): $(6u + 9v) + (4u - 9v) = 6 + (-1) \implies 10u = 5 \implies u = \frac{1}{2}$ Substitute $u = 1/2$ into (1): $2(1/2) + 3v = 2 \implies 1 + 3v = 2 \implies 3v = 1 \implies v = \frac{1}{3}$
Solve for x and y
$\frac{1}{\sqrt{x}} = \frac{1}{2} \implies \sqrt{x} = 2 \implies x = 4$ $\frac{1}{\sqrt{y}} = \frac{1}{3} \implies \sqrt{y} = 3 \implies y = 9$
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