🏆 Daily Math Board Challenge (2026 Edition)
Check whether (x + 1)² = 2(x − 3) is a quadratic equation.
🎯 Chapter Readiness Score35%
⚡ Key Formulas at a Glance
Formula (Hover/Click)
Objective Function
Maximize or Minimize Z = ax + by
Formula (Hover/Click)
Corner Point Theorem
Optimal value of Z occurs at corner point of feasible region
Formula (Hover/Click)
Feasible Region
Common region determined by all constraints including non-negativity
🔍
📊 Chapter Weightage Analytics: High Yield Topic in Board Papers
Years Included: Year 2024, Year 2023
📅 Year 2024 Board Examination Paper
Q1NCERT Standard • 2 Marks2 Marks
Evaluate the exact mathematical value for Linear Programming when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Linear Programming: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
Q2CBSE Board 2024 • 3 Marks3 Marks
Solve the exact board examination equation for Linear Programming: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
Q3NCERT Standard (Variant #3) • 2 Marks2 Marks
Evaluate the exact mathematical value for Linear Programming when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Linear Programming: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
Q4CBSE Board 2024 (Variant #4) • 3 Marks3 Marks
Solve the exact board examination equation for Linear Programming: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
Q5NCERT Standard (Variant #5) • 2 Marks2 Marks
Evaluate the exact mathematical value for Linear Programming when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Linear Programming: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
📅 Year 2023 Board Examination Paper
Q1CBSE Board 2024 (Variant #6) • 3 Marks3 Marks
Solve the exact board examination equation for Linear Programming: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
Q2NCERT Standard (Variant #7) • 2 Marks2 Marks
Evaluate the exact mathematical value for Linear Programming when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Linear Programming: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
Q3CBSE Board 2024 (Variant #8) • 3 Marks3 Marks
Solve the exact board examination equation for Linear Programming: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2
Q4NCERT Standard (Variant #9) • 2 Marks2 Marks
Evaluate the exact mathematical value for Linear Programming when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.
Step 2 (Substitution & Solution):
Apply standard theorem for Linear Programming: Result = (2)² + 3(5) = 4 + 15 = 19.
✔ Final Answer: 19
Q5CBSE Board 2024 (Variant #10) • 3 Marks3 Marks
Solve the exact board examination equation for Linear Programming: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.
✔ Final Answer: x = 3, y = 2