Heron's Formula
Board: GSEB | Class: Std 9
Comprehensive study notes for Heron's Formula by Ajay Yadav (Math King of Katargam). Master every concept with clear explanations, solved examples, and practice problems.
Key Concepts
Area of a Triangle
For a triangle with sides a, b, c, Heron’s formula gives the area without needing the height. Semi-perimeter: s = (a + b + c)/2.
Heron's Formula
Area = √[s(s-a)(s-b)(s-c)] where s is the semi-perimeter. This formula works for ALL types of triangles – scalene, isosceles, equilateral.
Area of Equilateral Triangle
For an equilateral triangle with side a: s = 3a/2. Using Heron’s formula: Area = √3/4 × a².
Application to Quadrilaterals
To find the area of a quadrilateral using Heron’s formula, divide it into two triangles by drawing a diagonal, find the area of each, and add them.
Important Formulas
| Semi-perimeter | s = (a + b + c)/2 |
| Heron’s Formula | Area = √[s(s-a)(s-b)(s-c)] |
| Equilateral Triangle | Area = (√3/4)a² |
| Isosceles Triangle | Area = (b/4)√4a² - b² where a = equal sides, b = base |
Solved Examples
Example 1: Find the area of a triangle with sides 3 cm, 4 cm, 5 cm.
Solution: s = (3+4+5)/2 = 6. Area = √[6(6-3)(6-4)(6-5)] = √6×3×2×1 = √36 = 6 cm². This is a 3-4-5 right triangle.
Example 2: Find the area of an equilateral triangle with side 6 cm.
Solution: Using direct formula: Area = (√3/4) × 6² = (√3/4) × 36 = 9√3 = 15.59 cm².
Example 3: A triangular park has sides 120 m, 80 m, and 80 m. Find its area.
Solution: s = (120+80+80)/2 = 140. Area = √[140(140-120)(140-80)(140-80)] = √140×20×60×60 = √10080000 = 3175 m².
Practice Questions
- Find the area of a triangle with sides 7 cm, 8 cm, 9 cm.
- The sides of a triangle are in ratio 12:17:25 and its perimeter is 540 cm. Find its area.
- Find the area of an equilateral triangle with perimeter 60 cm.
- A rhombus has perimeter 40 cm and one diagonal 12 cm. Find its area.
- The base of an isosceles triangle is 12 cm and perimeter is 32 cm. Find its area.
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