Determinants

⭐ Important Questions

1. Find area of triangle with vertices (1,0), (2,2), (4,3) using determinant.
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   Area = 12|1(2-3) - 0(2-4) + 1(6-8)|\n= 12|-1 + 0 - 2| = 32 sq units
2. Solve: x + 2y = 5, 3x - y = 1 using Cramer's rule.
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   D = |1 2; 3 -1| = -7\nD_x = |5 2; 1 -1| = -7\nD_y = |1 5; 3 1| = -14\nx = D_xD = 1, y = D_yD = 2