Monomath – CBSE | GSEB | IB | JEE Maths by Ajay Yadav (Math King of Katargam) – 15+ Years Experience. Study Notes, Video Lessons, Formula Sheets & PYQs.
← Back to chapters

Inverse Trigonometric Functions

Previous Year Questions (2022-2024)

📅 Year 2022

  1. Find principal value of cot^{-1}(-1√3).
    Show Solution
    cot^{-1}(-1√3) = π - cot^{-1}(1√3) = π - π/3 = 2π/3
  2. Prove: 2tan^{-1}(13) = tan^{-1}(34).
    Show Solution
    2tan^{-1}x = tan^{-1}(2x1-x2)\n= tan^{-1}(2/31-1/9) = tan^{-1}(2/38/9) = tan^{-1}(34)

📅 Year 2023

  1. Find principal value of cot^{-1}(-1√3).
    Show Solution
    cot^{-1}(-1√3) = π - cot^{-1}(1√3) = π - π/3 = 2π/3
  2. Prove: 2tan^{-1}(13) = tan^{-1}(34).
    Show Solution
    2tan^{-1}x = tan^{-1}(2x1-x2)\n= tan^{-1}(2/31-1/9) = tan^{-1}(2/38/9) = tan^{-1}(34)

📅 Year 2024

  1. Find principal value of cot^{-1}(-1√3).
    Show Solution
    cot^{-1}(-1√3) = π - cot^{-1}(1√3) = π - π/3 = 2π/3
  2. Prove: 2tan^{-1}(13) = tan^{-1}(34).
    Show Solution
    2tan^{-1}x = tan^{-1}(2x1-x2)\n= tan^{-1}(2/31-1/9) = tan^{-1}(2/38/9) = tan^{-1}(34)