Monomath – CBSE | GSEB | IB | JEE Maths by Ajay Yadav (Math King of Katargam) – 15+ Years Experience. Study Notes, Video Lessons, Formula Sheets & PYQs.
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Triangles

Previous Year Questions (2022-2024)

📅 Year 2022

  1. In triangle PQR, ST || QR, PS/SQ = 2/3 and PR = 10 cm. Find PT.
    Show Solution
    By BPT: PS/SQ = PT/TR = 2/3\nLet PT=2k, TR=3k\nPR = 2k+3k = 5k = 10 => k = 2\nPT = 4 cm
  2. Diagonals of trapezium ABCD (AB||CD) intersect at O. If AB=2CD, find ratio of areas of triangles AOB and COD.
    Show Solution
    In triangles AOB and COD:\nAB || CD => ∠OAB = ∠OCD, ∠OBA = ∠ODC\nTriangles are similar (AA)\nRatio of areas = (AB/CD)2 = (2/1)2 = 4:1

📅 Year 2023

  1. In triangle PQR, ST || QR, PS/SQ = 2/3 and PR = 10 cm. Find PT.
    Show Solution
    By BPT: PS/SQ = PT/TR = 2/3\nLet PT=2k, TR=3k\nPR = 2k+3k = 5k = 10 => k = 2\nPT = 4 cm
  2. Diagonals of trapezium ABCD (AB||CD) intersect at O. If AB=2CD, find ratio of areas of triangles AOB and COD.
    Show Solution
    In triangles AOB and COD:\nAB || CD => ∠OAB = ∠OCD, ∠OBA = ∠ODC\nTriangles are similar (AA)\nRatio of areas = (AB/CD)2 = (2/1)2 = 4:1

📅 Year 2024

  1. In triangle PQR, ST || QR, PS/SQ = 2/3 and PR = 10 cm. Find PT.
    Show Solution
    By BPT: PS/SQ = PT/TR = 2/3\nLet PT=2k, TR=3k\nPR = 2k+3k = 5k = 10 => k = 2\nPT = 4 cm
  2. Diagonals of trapezium ABCD (AB||CD) intersect at O. If AB=2CD, find ratio of areas of triangles AOB and COD.
    Show Solution
    In triangles AOB and COD:\nAB || CD => ∠OAB = ∠OCD, ∠OBA = ∠ODC\nTriangles are similar (AA)\nRatio of areas = (AB/CD)2 = (2/1)2 = 4:1