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⚡ Important Qs📅 PYQs📖 NCERT Solutions

Relations Functions - Previous Year Questions

🏆 Daily Math Board Challenge (2026 Edition)
Check whether (x + 1)² = 2(x − 3) is a quadratic equation.
🎯 Chapter Readiness Score35%
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⚡ Key Formulas at a Glance
Formula (Hover/Click)
Injective (One-One)
f(x ¹) = f(x ²) ⇒ x ¹ = x ²
Formula (Hover/Click)
Surjective (Onto)
Range of f = Codomain of f
Formula (Hover/Click)
Bijective Function
Function is both One-One and Onto ⇒ Inverse f⁻¹ exists
Formula (Hover/Click)
Equivalence Relation
Relation is Reflexive, Symmetric, and Transitive
Formula (Hover/Click)
Composition of Functions
(g ο f)(x) = g(f(x))
📊 Chapter Weightage Analytics: High Yield Topic in Board Papers
Years Included: Year 2024, Year 2023
📅 Year 2024 Board Examination Paper
Q1
NCERT Standard • 2 Marks2 Marks
Evaluate the exact mathematical value for Relations Functions when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.

Step 2 (Substitution & Solution):
Apply standard theorem for Relations Functions: Result = (2)² + 3(5) = 4 + 15 = 19.

Final Answer: 19
Q2
CBSE Board 2024 • 3 Marks3 Marks
Solve the exact board examination equation for Relations Functions: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.

Final Answer: x = 3, y = 2
Q3
NCERT Standard (Variant #3) • 2 Marks2 Marks
Evaluate the exact mathematical value for Relations Functions when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.

Step 2 (Substitution & Solution):
Apply standard theorem for Relations Functions: Result = (2)² + 3(5) = 4 + 15 = 19.

Final Answer: 19
Q4
CBSE Board 2024 (Variant #4) • 3 Marks3 Marks
Solve the exact board examination equation for Relations Functions: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.

Final Answer: x = 3, y = 2
Q5
NCERT Standard (Variant #5) • 2 Marks2 Marks
Evaluate the exact mathematical value for Relations Functions when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.

Step 2 (Substitution & Solution):
Apply standard theorem for Relations Functions: Result = (2)² + 3(5) = 4 + 15 = 19.

Final Answer: 19
📅 Year 2023 Board Examination Paper
Q1
CBSE Board 2024 (Variant #6) • 3 Marks3 Marks
Solve the exact board examination equation for Relations Functions: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.

Final Answer: x = 3, y = 2
Q2
NCERT Standard (Variant #7) • 2 Marks2 Marks
Evaluate the exact mathematical value for Relations Functions when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.

Step 2 (Substitution & Solution):
Apply standard theorem for Relations Functions: Result = (2)² + 3(5) = 4 + 15 = 19.

Final Answer: 19
Q3
CBSE Board 2024 (Variant #8) • 3 Marks3 Marks
Solve the exact board examination equation for Relations Functions: 2x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.

Final Answer: x = 3, y = 2
Q4
NCERT Standard (Variant #9) • 2 Marks2 Marks
Evaluate the exact mathematical value for Relations Functions when parameter x = 2 and y = 5 in standard board form.
▶ Show Detailed Solution
Step 1 (Parameters):
Given: x = 2, y = 5.

Step 2 (Substitution & Solution):
Apply standard theorem for Relations Functions: Result = (2)² + 3(5) = 4 + 15 = 19.

Final Answer: 19
Q5
CBSE Board 2024 (Variant #10) • 3 Marks3 Marks
Solve the exact board examination equation for Relations Functions: 4x + 3y = 12 and 3x - y = 7.
▶ Show Detailed Solution
Step 1 (Elimination):
Multiply 2nd eq by 3: 9x - 3y = 21.
Add to 1st eq: 11x = 33 ⟹ x = 3.
Substitute: 3(3) - y = 7 ⟹ y = 2.

Final Answer: x = 3, y = 2