Monomath – CBSE | GSEB | IB | JEE Maths by Ajay Yadav (Math King of Katargam) – 15+ Years Experience. Study Notes, Video Lessons, Formula Sheets & PYQs.
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Areas Related to Circles

Previous Year Questions (2022-2024)

📅 Year 2022

  1. Find area of sector of radius 14 cm with angle 60°. Also find perimeter.
    Show Solution
    Area = 60360 x 227 x 142 = 16 x 227 x 196\n= 16 x 616 = 102.67 cm2\nPerimeter = 2r + theta360 x 2πr\n= 28 + 16 x 2 x 227 x 14 = 28 + 14.67 = 42.67 cm
  2. A chord subtends 90° at center of circle radius 14 cm. Find area of corresponding minor segment.
    Show Solution
    Area of sector = 90360 x π x 196 = 49π cm2\nArea of triangle = 12 x 14 x 14 = 98 cm2\nArea of minor segment = 49π - 98 = 49(227 - 2) = 49(22-147) = 49 x 87 = 56 cm2

📅 Year 2023

  1. Find area of sector of radius 14 cm with angle 60°. Also find perimeter.
    Show Solution
    Area = 60360 x 227 x 142 = 16 x 227 x 196\n= 16 x 616 = 102.67 cm2\nPerimeter = 2r + theta360 x 2πr\n= 28 + 16 x 2 x 227 x 14 = 28 + 14.67 = 42.67 cm
  2. A chord subtends 90° at center of circle radius 14 cm. Find area of corresponding minor segment.
    Show Solution
    Area of sector = 90360 x π x 196 = 49π cm2\nArea of triangle = 12 x 14 x 14 = 98 cm2\nArea of minor segment = 49π - 98 = 49(227 - 2) = 49(22-147) = 49 x 87 = 56 cm2

📅 Year 2024

  1. Find area of sector of radius 14 cm with angle 60°. Also find perimeter.
    Show Solution
    Area = 60360 x 227 x 142 = 16 x 227 x 196\n= 16 x 616 = 102.67 cm2\nPerimeter = 2r + theta360 x 2πr\n= 28 + 16 x 2 x 227 x 14 = 28 + 14.67 = 42.67 cm
  2. A chord subtends 90° at center of circle radius 14 cm. Find area of corresponding minor segment.
    Show Solution
    Area of sector = 90360 x π x 196 = 49π cm2\nArea of triangle = 12 x 14 x 14 = 98 cm2\nArea of minor segment = 49π - 98 = 49(227 - 2) = 49(22-147) = 49 x 87 = 56 cm2