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Some Applications of Trigonometry
Previous Year Questions (2022-2024)
Year 2022
- A tower stands vertically. From a point 100 m away, angle of elevation is 60°. Find tower height.
Show Solution
tan 60 = h100\nh = 100 x √3 = 100√3 m ≈ 173.2 m - From top of 7 m building, angle of depression of a tower top is 45° and bottom is 60°. Find tower height.
Show Solution
Let tower height = h. Distance between = d.\ntan 45 = h-7d => d = h-7\ntan 60 = hd => √3 = hh-7\nh = (h-7)√3 => h = 7√3/(√3-1) = 7√3(√3+1)/2\nh = 7(3+√3)2 m
Year 2023
- A tower stands vertically. From a point 100 m away, angle of elevation is 60°. Find tower height.
Show Solution
tan 60 = h100\nh = 100 x √3 = 100√3 m ≈ 173.2 m - From top of 7 m building, angle of depression of a tower top is 45° and bottom is 60°. Find tower height.
Show Solution
Let tower height = h. Distance between = d.\ntan 45 = h-7d => d = h-7\ntan 60 = hd => √3 = hh-7\nh = (h-7)√3 => h = 7√3/(√3-1) = 7√3(√3+1)/2\nh = 7(3+√3)2 m
Year 2024
- A tower stands vertically. From a point 100 m away, angle of elevation is 60°. Find tower height.
Show Solution
tan 60 = h100\nh = 100 x √3 = 100√3 m ≈ 173.2 m - From top of 7 m building, angle of depression of a tower top is 45° and bottom is 60°. Find tower height.
Show Solution
Let tower height = h. Distance between = d.\ntan 45 = h-7d => d = h-7\ntan 60 = hd => √3 = hh-7\nh = (h-7)√3 => h = 7√3/(√3-1) = 7√3(√3+1)/2\nh = 7(3+√3)2 m