Matrices and Determinants
Board: JEE Main |Exam:JEEMain
JEEMainstudynotesforMatricesandDeterminantsbyAjayYadav.ThischaptercoversallconceptsrequiredforJEEMainwithproblem-solvingtechniques.
KeyConcepts
MatrixOperations
Multiplication,transpose,trace.Properties:(AB)’=B’A’.(ABC)⁻¹=C⁻¹B⁻¹A⁻¹.
AdjointandInverse
A(adjA)=(adjA)A=|A|I.A⁻¹=adjA/|A|. |A⁻¹|=1/|A|.(AB)⁻¹=B⁻¹A⁻¹.
PropertiesofDeterminants
|A’|=|A|.Row/columninterchangeflipssign.Identicalrows/cols⇒|A|=0. |kA|=kⁿ|A|. |AB|=|A||B|.
System of Equations
Cramer’s rule: xj=|Aj|/|A|. Consistency: |A|≠0 ⇒ unique. |A|=0 and (adjA)B=0 ⇒ infinite. |A|=0 and (adjA)B≠0 ⇒ no solution.
Important Formulas
| |kA| | kⁿ|A| for n×n matrix |
| |AB| | |A||B| |
| A⁻¹ | adjA/|A| |
| Cramer’s rule | xj = |Aj|/|A| |
Solved Examples
Example 1: For A=(1234), find |A|, adjA, A⁻¹.
Solution: |A|=-2. adjA=(4-2-31). A⁻¹=(-211.5-0.5).
Example 2: Test consistency: x+2y=5, 3x+6y=15.
Solution: |A|=6-6=0. (adjA)B=(6-2-31)(515)=(00). Infinite solutions.
Practice Questions
- Find |A| for A=(123456789).
- Find A⁻¹ for A=(1235).
- Solve: 2x+3y=1, x-y=3 using Cramer’s rule.
- If A=(cos&theta-sin&thetasin&thetacos&theta), show A’A=I.
- Find conditions for k if system has infinite solutions: x+2y=5, 3x+ky=15.