Quadratic Equations

Quadratic Equations

Board: CBSE | Class: Class 10

Comprehensive study notes for Quadratic Equations by Ajay Yadav (Math King of Katargam). Master every concept with clear explanations, solved examples, and practice problems.

Key Concepts

Standard Form

A quadratic equation in x is of the form ax² + bx + c = 0 where a ≠ 0. The highest power of the variable is 2.

Solving by Factorization

Write ax² + bx + c as (px + q)(rx + s) = 0. Then set each factor to zero: px + q = 0 or rx + s = 0. This gives the roots.

Solving by Completing the Square

Rewrite ax² + bx + c = 0 as (x + b/2a)² = (b² – 4ac)/4a². Take square root on both sides. This method derives the quadratic formula.

Quadratic Formula

x = (-b ± b² – 4ac)/2a. The expression D = b² – 4ac is called the discriminant.

Nature of Roots

D > 0: Two distinct real roots. D = 0: One real root (repeated). D < 0: No real roots (complex conjugates).

Word Problems

Quadratic equations model many real-world situations: area problems, number problems, time-speed-distance, age problems, and profit-loss scenarios.

Important Formulas

Standard Formax² + bx + c = 0, a ≠ 0
Quadratic Formulax = (-b ± √D)/2a where D = b² - 4ac
DiscriminantD = b² - 4ac
D > 0Two distinct real roots
D = 0One real root (repeated)
D < 0No real roots

Solved Examples

Example 1: Solve x² – 5x + 6 = 0 by factorization.

Solution: x² – 5x + 6 = (x-2)(x-3) = 0. x = 2 or x = 3.

Example 2: Solve 2x² – 5x + 3 = 0 using the formula.

Solution: a=2, b=-5, c=3. D = 25 – 24 = 1. x = (5 ± 1)/4. x = 3/2 or x = 1.

Example 3: Find the discriminant of x² + 4x + 5 = 0.

Solution: D = 16 – 20 = -4. Since D < 0, no real roots exist.

Practice Questions

  1. Solve: 2x² – 7x + 3 = 0.
  2. Find k such that x² + kx + 4 = 0 has equal roots.
  3. The area of a rectangle is 240 cm². Its length is 8 cm more than width. Find dimensions.
  4. Solve: 9x² + 7x – 2 = 0 using the quadratic formula.
  5. If the sum of two numbers is 15 and sum of squares is 113, find the numbers.

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