Inverse Trigonometric Functions

⭐ Important Questions

1. Find principal value of cot^{-1}(-1√3).
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   cot^{-1}(-1√3) = π - cot^{-1}(1√3) = π - π/3 = 2π/3
2. Prove: 2tan^{-1}(13) = tan^{-1}(34).
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   2tan^{-1}x = tan^{-1}(2x1-x²)\n= tan^{-1}(2/31-1/9) = tan^{-1}(2/38/9) = tan^{-1}(34)