← CBSE Class 10
Coordinate Geometry
Chapter Overview
Coordinate geometry uses the Cartesian coordinate system to locate points using ordered pairs (x, y). The distance between points (x1, y1) and (x2, y2) is √((x2-x1)2 + (y2-y1)2). The section formula finds the coordinates of a point dividing a line segment in a given ratio. For internal division: ((mx2+nx1)/(m+n), (my2+ny1)/(m+n)). The midpoint formula is a special case of the section formula. The area of a triangle with vertices (x1, y1), (x2, y2), (x3, y3) is 1/2|x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|.
Topics Covered
- Cartesian System
- Distance Formula
- Section Formula
- Midpoint Formula
- Area of Triangle
- Collinearity
- Quadrilateral Area
Key Formulas
d = √(x2-x1)2 + (y2-y1)2
P = ((mx2+nx1)/(m+n), (my2+ny1)/(m+n))
Midpoint = ((x1+x2)/2, (y1+y2)/2)
Area = 1/2|x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|
Real-World Applications
Applications: GPS navigation, computer graphics, map systems, architecture, game development.
Study Tips
Tip: Memorize distance and section formulas
Tip: Practice area formula with different vertex orders
Tip: Solve NCERT exemplar problems